Special Trigonometric Integrals
In the study of Fourier Series, you will find that every continuous
function f on an interval [-L,L] can be expressed on that interval
as an infinite series of sines and cosines. For example, if the
interval is [-p,p ],
| f(x) = A0 + |
¥
å k = 1
|
[Akcos(kx) + Bksin(kx)] |
where the constants are given by integrals involving f.
The theory of Fourier series relies on the fact that the functions
| 1, cos(x),
sin(x), cos(2x),
sin(2x), ¼, cos(nx),
sin(nx), ¼ |
form an orthogonal set:
The integral of the product of any 2 of these functions over
[-p, p ] is 0.
Here, we will verify this fact.
We will use the following trigonometric identities:
| sin(A)sin(B) |
= |
1 2
|
[cos(A-B)-cos(A+B)] |
| cos(A)cos(B) |
= |
1 2
|
[cos(A-B)+cos(A+B)] |
| sin(A)cos(B) |
= |
1 2
|
[sin(A-B)+sin(A+B)] |
We have six general integrals to evaluate to prove the orthogonality
of the set {1, cosx, sinx, ¼}.
In each of the following, we assume m and n are distinct positive integers.
-
-
-
ó õ |
p
-p
|
sin(nx)cos(nx) dx |
|
= |
|
-
ó õ |
p
-p
|
sin(mx)sin(nx) dx |
|
= |
ó õ |
p
-p
|
1 2
|
[cos(m-n)x-cos(m+n)x] dx |
|
|
= |
sin[(m-n)x] 2(m-n) |
- |
sin[(m+n)x] 2(m+n) |
ô ô ô |
p
-p |
|
|
= |
0 |
-
|
|
= |
ó õ |
p
-p
|
1 2
|
[cos(m-n)x+cos(m+n)x] dx |
|
|
= |
sin[(m-n)x] 2(m-n) |
- |
sin[(m+n)x] 2(m+n) |
ô ô ô |
p
-p |
|
|
= |
0. |
-
ó õ |
p
-p
|
sin(mx)cos(nx) dx |
|
= |
ó õ |
p
-p
|
1 2
|
[sin(m-n)x+sin(m+n)x] dx |
|
|
= |
cos[(m-n)x] 2(m-n) |
- |
cos[(m+n)x] 2(m+n) |
ô ô ô |
p
-p |
|
|
= |
0. |
We have now shown that {1, cos(x), sin(x), cos(2x), sin(2x),
¼} is indeed an orthogonal set of functions!
In the following Exploration, graph functions sin(mx)sin(nx), sin(mx)cos(nx),
and cos(mx)cos(nx) for various values of m and n and observe the interesting
curves that result.
Exploration
Key Concept
The theory of Fourier series relies on the fact that the functions
| 1, cos(x),
sin(x), cos(2x),
sin(2x), ¼, cos(nx),
sin(nx), ¼ |
form an orthogonal set:
The integral of the product of any 2 of these functions over
[-p, p ] is 0.